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What is the difference between Kc and Kp

Kc is the equilibrium constant expressed with concentrations (mol L⁻¹) and applies to any phase, while Kp uses partial pressures (atm) for gases; they are linked by Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n} where Δn\Delta n is the change in moles of gas.

Chemistry · Chemical equilibrium


Kc is defined as Kc=[products]νp[reactants]νrK_c = \frac{[products]^{\nu_{p}}}{[reactants]^{\nu_{r}}} using molarity. Kp replaces each concentration with the corresponding partial pressure: Kp=(Pproducts)νp(Preactants)νrK_p = \frac{(P_{products})^{\nu_{p}}}{(P_{reactants})^{\nu_{r}}}. Use Kc when concentrations are measured, and Kp when only gas pressures are known.

Relation between Kc and Kp

Convert Kc to Kp for a gas‑phase reaction

  1. 1Write the balanced equation and count gas moles on each side.
  2. 2Calculate Δn=νgas,productsνgas,reactants\Delta n = \sum \nu_{gas,products} - \sum \nu_{gas,reactants}.
  3. 3Apply Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n} using R = 0.08206 L·atm·mol⁻¹·K⁻¹ and the temperature in kelvin.

Key points to remember

  • Kc uses molarity, Kp uses pressure.
  • Δn\Delta n can be zero; then Kp=KcK_p = K_c.
  • Units cancel in the ratio, so Kc and Kp are dimensionless in practice.

Example calculation for 2NH₃(g) ⇌ N₂(g)+3H₂(g) at 400 K

\(\Delta n\)KcKp
-21.22.1\times10^{-4}
00.450.45

Check yourself

For the reaction N₂(g)+3H₂(g)⇌2NH₃(g) with Δn=2\Delta n = -2 at 500 K, if Kc=0.5K_c = 0.5, what is KpK_p?

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