Does adding a catalyst shift equilibrium
Adding a catalyst does not shift the position of equilibrium; it only speeds up the rate at which equilibrium is reached. The equilibrium constant K remains the same because the catalyst lowers the activation energy for both the forward and reverse reactions equally.
Chemistry · Chemical equilibrium
A catalyst provides an alternative pathway with lower activation energy for both directions of a reversible reaction. For example, in the Haber process N₂+3H₂⇌2NH₃, iron speeds up the formation of NH₃ and its decomposition, but the ratio of product to reactant concentrations at equilibrium stays unchanged.
Why the equilibrium constant stays the same
Key reasons the equilibrium position is unaffected:
- Catalyst lowers activation energy for forward and reverse reactions equally
- Both forward () and reverse () rate constants are multiplied by the same factor
- Equilibrium constant K = / therefore does not change
How to see the effect experimentally:
- 1Measure concentrations of N₂, H₂, and NH₃ over time without a catalyst until they stop changing
- 2Add iron catalyst and repeat the measurement under identical temperature and pressure
- 3Notice that the same final concentrations are reached faster
Catalyst effect on rate constants (arbitrary units):
| Condition | k_f (s⁻¹) | k_r (s⁻¹) |
|---|---|---|
| No catalyst | 0.01 | 0.005 |
| With catalyst | 0.10 | 0.05 |
Check yourself
Which statement correctly explains why a catalyst does not change the equilibrium constant?
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