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How to find the limiting reactant

The limiting reactant is the reactant that will be completely consumed first, determining the maximum amount of product formed. Identify it by converting each reactant’s mass (or moles) to moles, dividing by its stoichiometric coefficient, and the smallest resulting ratio is the limiting reactant.

Chemistry · Stoichiometry


To find the limiting reactant, start with the balanced chemical equation, then turn the given masses (or volumes) of each reactant into moles using their molar masses. Next, divide each mole amount by the coefficient that appears in the balanced equation; the smallest resulting value tells you which reactant runs out first.

Example: Combustion of propane

Follow these calculations for the reaction

  1. 1Write the balanced equation: C3H8+5O23CO2+4H2O\mathrm{C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O}.
  2. 2Convert masses to moles: 40 g C3H8\mathrm{C_3H_8} (M=44.1 g·mol⁻¹) gives 0.91 mol; 200 g O2\mathrm{O_2} (M=32.0 g·mol⁻¹) gives 6.25 mol.
  3. 3Divide by coefficients: 0.91/1 = 0.91, 6.25/5 = 1.25.
  4. 4The smallest quotient is 0.91, so propane is the limiting reactant.

Data you need before you start

  • Balanced chemical equation
  • Mass or volume of each reactant
  • Molar mass of each reactant

Calculated moles and quotients

ReactantMolesCoefficientQuotient
C₃H₈0.9110.91
O₂6.2551.25

Check yourself

In the propane combustion example, which reactant is identified as limiting and why?

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