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How do you know if a reaction is endothermic or exothermic

You determine whether a reaction is endothermic or exothermic by the sign of its enthalpy change (ΔH). A negative ΔH means heat is released to the surroundings, so the reaction is exothermic; a positive ΔH means heat is absorbed, so the reaction is endothermic. Calorimetry or bond‑energy calculations give the sign.

Chemistry · Thermochemistry


In thermochemistry the heat exchanged between reacting substances and their surroundings is quantified by the enthalpy change, ΔH. A negative ΔH indicates that the reaction releases heat to the surroundings, so the temperature of the surroundings rises – this is an exothermic process. A positive ΔH means heat is taken from the surroundings, causing a temperature drop – an endothermic process.

Sign of ΔH and Heat Flow

Calorimetry directly measures the temperature change of a known mass of water (or another solvent) that absorbs or releases heat during the reaction. Using q=mcΔTq = m c \Delta T you calculate the heat q transferred, then divide by the number of moles reacting to obtain ΔH per mole. The sign of q (and therefore ΔH) tells you whether the reaction is endothermic or exothermic.

Three quick ways to decide whether a reaction is endothermic or exothermic

  • Measure the temperature change of the surroundings
  • Look up ΔH in a thermodynamic table
  • Calculate ΔH from bond‑energy differences

Procedure to obtain ΔH from a simple calorimetry experiment

  1. 1Weigh a known mass of water and record its initial temperature.
  2. 2Carry out the reaction in the water and record the final temperature.
  3. 3Compute q=mcΔTq = m c \Delta T with c=4.18 J g1K1c = 4.18\ \text{J g}^{-1}\text{K}^{-1}.
  4. 4Divide q by the moles of reactant to get ΔH per mole and note the sign.

Typical ΔH values for common reactions

ReactionΔH (kJ/mol)
Combustion of methane-890
Dissolution of NH₄NO₃ in water+26

Example: 5.00 g of ammonium nitrate (NH₄NO₃) dissolves in 100 g of water. The temperature falls from 25.0 °C to 22.3 °C. Using q=mcΔTq = m c \Delta T with m=100 gm = 100\ \text{g} and c=4.18 J g1K1c = 4.18\ \text{J g}^{-1}\text{K}^{-1} gives q=100×4.18×(22.325.0)=1.13×103 Jq = 100 \times 4.18 \times (22.3-25.0) = -1.13\times10^{3}\ \text{J}. The negative q indicates heat was absorbed by the system, so ΔH = +1.13 kJ for the 5.00 g sample. Converting to per‑mole basis (molar mass 80.04 g mol⁻¹) yields ΔH ≈ +18 kJ mol⁻¹, confirming an endothermic process.

Check yourself

If a reaction causes the temperature of the surrounding water to drop, what is the sign of ΔH?

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